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I just got finished replacing the tie bars for my P40 Switch Track from Fx Bricks. It gave me an opportunity of looking pretty closely at the switch itself and I started wondering how it turned off power on the inactive pathway. I just didn't see a way. At first I thought the Switch Rail's connection may somehow depend on if it's switched or not, but it was backwards from that. So, tonight I powered the track up and switched back and forth. And, at all times, both the diverging route and the straight route were powered. (Yes, if I pulled the jumper, there was no power on the diverging route at all times regardless of how the switch was positioned which is not a solution.) So, how would you have a siding for a train if it's always powered regardless of how the switch is positioned? The only possible way I can think of is this switch requires DCC so the train itself knows when it can go or not. I really hope I have something wrong because if I don't, then the P40 Switch Track is not compatible with 9v trains. Yes, it can deliver power, but it can't shut it off if the path is not active. Think of a yard ladder. Every lane would be powered at all times. There's no stopping trains then. All of the trains would be moving. Please let me know I'm missing something because if I'm not I spent a lot of money for nothing that I can use and I'm stuck with Lego's switches for a long time to come. (Yes, I'm stuck on 9v and happy with it, but trying to improve it.) ------ Later addition ----- Ok, I just reread the FAQ that's included in the product guide: >Does changing the switch route also switch the electrical power to the route? >No. The P40 switch does not switch the electrical power between the straight and diverging routes. Both routes are "live" and their corresponding rails are connected together. Then how would you have a siding to park a train? Or a yard ladder with multiple trains parked? All of the track would be powered at all times. Are they assuming DCC for everything? -Corey
