mav2010

Hi, I would also like to have the parts list, please. Thank you!

Thanks for the confirmation, Bruno! My calculations above are already with the swapped gears. I was basically just confused whether the "green gears" or the other alternative with all 16 gears is the "faster" one. Regarding the battery box: I am using the Mould King battery Box with motor driver chips exchanged for something more solid (RZ7889 chips). The big advantage is, that with the Mould King battery box you can simultaneously control up to three channel. So I have 2 L Motors each on Channel A and B and can operate them all together just with the A buttons. That is quite convenient. And the driver chips are also quite powerful. Nowhere near the BuWizz of course, but at least way better than the CaDa battery box, which fails completely in driving this setup. And way cheaper as well. The CaDa L motors are really impressive. They are really strong and with quite low amperage need for the torque they deliver. I have built the complete drivetrain, so up to roughly step C100. In this setup, the 1 Mould King Box is driving the model quite well in all gears. I will now continue with the build. Let's see what the added weight of all the red parts now does to the performance!

Hi everyone, I am experimenting with a 4x CaDa L Motor setup in the Pista at the moment. Since I am still learning about gearboxes and gear ratios, I would like to check if my understanding is correct. I have set up the motors based on Brunos suggestion on page 11: Do I read this setup correctly, that only the green gears in the picture result in a 1:1.667 (20/12) ratio? (1 turn of the 12 gear at the motor --> 0.6 turns of the 20 helper gear --> 1 turn of the 12 gear --> 1 turn of the 20 gear --> 1.667 turns of the 12 gear --> 1.667 turns of the 16 gear --> 1.667 turns of the 16 gear). And then an understanding question on Brunos calculation. Isn't the result of that 2.8:1? That's at least the result, when I enter it into Sariels calculator. What I plan to do is to combine the setup with the green gears above with the swapped gears behind the differential (instead of 2x20/1x24 use 2x24/1x20). That should give me then 1.GEAR: 20/12 + 12/20 + 24/20 + 20/28 = 1.17 : 1 2.GEAR: 20/12 + 12/20 + 20/28 = 1.4 : 1 3.GEAR: 20/12 + 24/20 + 20/28 = 1 : 1.4 4.GEAR: 20/12 + 20/28 = 1 : 1.2 So if I understand this all correctly, then this combination should be (in theory) the fastest setup, assuming that the torque of the 4 CaDA L motors is still enough in gear 3 to move the car. Please check my calculations as I am profoundly confused by now...